Albert had
38 the number of pens that Liam had at first. After Liam gave Albert 72 of his pens, Albert had
35 the number of pens that Liam had. How many pens did Liam have in the end?
|
Albert |
Liam |
Total |
Before |
3x8 = 24 u |
8x8 = 64 u |
11x8 = 88 u |
Change |
+ 9 u |
- 9 u |
|
After |
3x11 = 33 u |
5x11 = 55 u |
8x11 = 88 u |
The total number of pens that Albert and Liam had at first and in the end remains unchanged. Make the total number of pens the same. LCM of 11 and 8 is 88.
Number of pens that Liam gave Albert
= 33 u - 24 u
= 9 u
9 u = 72
1 u = 72 ÷ 9 = 8
Number of pens that Liam had in the end
= 55 u
= 55 x 8
= 440
Answer(s): 440