Fred had
25 the number of beads that Ian had at first. After Ian gave Fred 55 of his beads, Fred had
35 the number of beads that Ian had. How many beads did Fred have at first?
|
Fred |
Ian |
Total |
Before |
2x8 = 16 u |
5x8 = 40 u |
7x8 = 56 u |
Change |
+ 5 u |
- 5 u |
|
After |
3x7 = 21 u |
5x7 = 35 u |
8x7 = 56 u |
The total number of beads that Fred and Ian had at first and in the end remains unchanged. Make the total number of beads the same. LCM of 7 and 8 is 56.
Number of beads that Ian gave Fred
= 21 u - 16 u
= 5 u
5 u = 55
1 u = 55 ÷ 5 = 11
Number of beads that Fred had at first
= 16 u
= 16 x 11
= 176
Answer(s): 176