Ahmad had
38 the number of coins that Mark had at first. After Mark gave Ahmad 34 of his coins, Ahmad had
45 the number of coins that Mark had. How many coins did Mark have in the end?
|
Ahmad |
Mark |
Total |
Before |
3x9 = 27 u |
8x9 = 72 u |
11x9 = 99 u |
Change |
+ 17 u |
- 17 u |
|
After |
4x11 = 44 u |
5x11 = 55 u |
9x11 = 99 u |
The total number of coins that Ahmad and Mark had at first and in the end remains unchanged. Make the total number of coins the same. LCM of 11 and 9 is 99.
Number of coins that Mark gave Ahmad
= 44 u - 27 u
= 17 u
17 u = 34
1 u = 34 ÷ 17 = 2
Number of coins that Mark had in the end
= 55 u
= 55 x 2
= 110
Answer(s): 110