Tommy had
38 the number of coins that Cody had at first. After Cody gave Tommy 12 of his coins, Tommy had
37 the number of coins that Cody had. How many coins did Cody have in the end?
| |
Tommy |
Cody |
Total |
| Before |
3x10 =
30 u |
8x10 =
80 u |
11x10 =
110 u |
| Change |
+ 3 u |
- 3 u |
|
| After |
3x11 =
33 u |
7x11 =
77 u |
10x11 =
110 u |
The total number of coins that Tommy and Cody had at first and in the end remains unchanged. Make the total number of coins the same. LCM of 11 and 10 is 110.
Number of coins that Cody gave Tommy
= 33 u - 30 u
= 3 u
3 u = 12
1 u = 12 ÷ 3 = 4
Number of coins that Cody had in the end
= 77 u
= 77 x 4
= 308
Answer(s): 308
