Xavier had
58 the number of beads that Neave had at first. After Neave gave Xavier 70 of his beads, Xavier had
45 the number of beads that Neave had. How many beads did Neave have in the end?
| |
Xavier |
Neave |
Total |
| Before |
5x9 =
45 u |
8x9 =
72 u |
13x9 =
117 u |
| Change |
+ 7 u |
- 7 u |
|
| After |
4x13 =
52 u |
5x13 =
65 u |
9x13 =
117 u |
The total number of beads that Xavier and Neave had at first and in the end remains unchanged. Make the total number of beads the same. LCM of 13 and 9 is 117.
Number of beads that Neave gave Xavier
= 52 u - 45 u
= 7 u
7 u = 70
1 u = 70 ÷ 7 = 10
Number of beads that Neave had in the end
= 65 u
= 65 x 10
= 650
Answer(s): 650
