David had
58 the number of coins that Henry had at first. After Henry gave David 8 of his coins, David had
34 the number of coins that Henry had. How many coins did Henry have in the end?
| |
David |
Henry |
Total |
| Before |
5x7 =
35 u |
8x7 =
56 u |
13x7 =
91 u |
| Change |
+ 4 u |
- 4 u |
|
| After |
3x13 =
39 u |
4x13 =
52 u |
7x13 =
91 u |
The total number of coins that David and Henry had at first and in the end remains unchanged. Make the total number of coins the same. LCM of 13 and 7 is 91.
Number of coins that Henry gave David
= 39 u - 35 u
= 4 u
4 u = 8
1 u = 8 ÷ 4 = 2
Number of coins that Henry had in the end
= 52 u
= 52 x 2
= 104
Answer(s): 104
