Ivan had
25 the number of beads that Gabriel had at first. After Gabriel gave Ivan 100 of his beads, Ivan had
45 the number of beads that Gabriel had. How many beads did Gabriel have in the end?
| |
Ivan |
Gabriel |
Total |
| Before |
2x9 =
18 u |
5x9 =
45 u |
7x9 =
63 u |
| Change |
+ 10 u |
- 10 u |
|
| After |
4x7 =
28 u |
5x7 =
35 u |
9x7 =
63 u |
The total number of beads that Ivan and Gabriel had at first and in the end remains unchanged. Make the total number of beads the same. LCM of 7 and 9 is 63.
Number of beads that Gabriel gave Ivan
= 28 u - 18 u
= 10 u
10 u = 100
1 u = 100 ÷ 10 = 10
Number of beads that Gabriel had in the end
= 35 u
= 35 x 10
= 350
Answer(s): 350
