Howard had
35 the number of pens that Tom had at first. After Tom gave Howard 35 of his pens, Howard had
45 the number of pens that Tom had. How many pens did Tom have in the end?
| |
Howard |
Tom |
Total |
| Before |
3x9 =
27 u |
5x9 =
45 u |
8x9 =
72 u |
| Change |
+ 5 u |
- 5 u |
|
| After |
4x8 =
32 u |
5x8 =
40 u |
9x8 =
72 u |
The total number of pens that Howard and Tom had at first and in the end remains unchanged. Make the total number of pens the same. LCM of 8 and 9 is 72.
Number of pens that Tom gave Howard
= 32 u - 27 u
= 5 u
5 u = 35
1 u = 35 ÷ 5 = 7
Number of pens that Tom had in the end
= 40 u
= 40 x 7
= 280
Answer(s): 280
