Howard had
38 the number of erasers that Tim had at first. After Tim gave Howard 48 of his erasers, Howard had
34 the number of erasers that Tim had. How many erasers did Tim have in the end?
| |
Howard |
Tim |
Total |
| Before |
3x7 =
21 u |
8x7 =
56 u |
11x7 =
77 u |
| Change |
+ 12 u |
- 12 u |
|
| After |
3x11 =
33 u |
4x11 =
44 u |
7x11 =
77 u |
The total number of erasers that Howard and Tim had at first and in the end remains unchanged. Make the total number of erasers the same. LCM of 11 and 7 is 77.
Number of erasers that Tim gave Howard
= 33 u - 21 u
= 12 u
12 u = 48
1 u = 48 ÷ 12 = 4
Number of erasers that Tim had in the end
= 44 u
= 44 x 4
= 176
Answer(s): 176
