Albert had
38 the number of coins that Nick had at first. After Nick gave Albert 24 of his coins, Albert had
37 the number of coins that Nick had. How many coins did Nick have in the end?
|
Albert |
Nick |
Total |
Before |
3x10 = 30 u |
8x10 = 80 u |
11x10 = 110 u |
Change |
+ 3 u |
- 3 u |
|
After |
3x11 = 33 u |
7x11 = 77 u |
10x11 = 110 u |
The total number of coins that Albert and Nick had at first and in the end remains unchanged. Make the total number of coins the same. LCM of 11 and 10 is 110.
Number of coins that Nick gave Albert
= 33 u - 30 u
= 3 u
3 u = 24
1 u = 24 ÷ 3 = 8
Number of coins that Nick had in the end
= 77 u
= 77 x 8
= 616
Answer(s): 616