Justin had
25 the number of coins that Luke had at first. After Luke gave Justin 20 of his coins, Justin had
35 the number of coins that Luke had. How many coins did Luke have in the end?
| |
Justin |
Luke |
Total |
| Before |
2x8 =
16 u |
5x8 =
40 u |
7x8 =
56 u |
| Change |
+ 5 u |
- 5 u |
|
| After |
3x7 =
21 u |
5x7 =
35 u |
8x7 =
56 u |
The total number of coins that Justin and Luke had at first and in the end remains unchanged. Make the total number of coins the same. LCM of 7 and 8 is 56.
Number of coins that Luke gave Justin
= 21 u - 16 u
= 5 u
5 u = 20
1 u = 20 ÷ 5 = 4
Number of coins that Luke had in the end
= 35 u
= 35 x 4
= 140
Answer(s): 140
