Mrs Chia gave Kimberly and Irene some money each on Monday. On Tuesday, Kimberly gave
14 of the amount she had to Irene. On Wednesday, Irene gave
13 of the amount she had to Kimberly. In the end, Kimberly had $23 and Irene had $10. How much did Irene had more than Kimberly at first?
|
Kimberly |
Irene |
Total |
Before 1 |
4 u |
? |
$33 |
Change 1 |
- 1 u |
+ 1 u |
|
After 1 |
3 u |
3 p |
$33 |
Before 2 |
$23 - 1 p |
3 p |
$33 |
Change 2 |
+ 1 p |
- 1 p |
|
After 2 |
$23 |
2 p ($10) |
$33 |
Amount that Irene had in the end = 2 p
2 p = 10
1 p = 10 ÷ 2 = 5
Working backwards.
Amount that Kimberly had after giving to Irene on Tuesday
= 23 - 1 p
= 23 - 5
= $18
3 u = 18
1 u = 18 ÷ 3 = 6
Amount that Kimberly had at first
= 4 u
= 4 x 6
= $24
Total amount that Kimberly and Irene had
= 23 + 10
= $33
Amount that Irene had at first
= 33 - 24
= $9
Amount that Kimberly had more than Irene
= 24 - 9
= $15
Answer(s): $15