Mrs Thia gave Marion and Hilda some money each on Wednesday. On Thursday, Marion gave
13 of the amount she had to Hilda. On Friday, Hilda gave
14 of the amount she had to Marion. In the end, Marion had $22 and Hilda had $6. How much did Hilda had more than Marion at first?
| |
Marion |
Hilda |
Total |
| Before 1 |
3 u |
? |
$28 |
| Change 1 |
- 1 u |
+ 1 u |
|
| After 1 |
2 u |
4 p |
$28 |
| Before 2 |
$22 - 1 p |
4 p |
$28 |
| Change 2 |
+ 1 p |
- 1 p |
|
After 2 |
$22 |
3 p
($6) |
$28 |
Amount that Hilda had in the end = 3 p
3 p = 6
1 p = 6 ÷ 3 = 2
Working backwards.
Amount that Marion had after giving to Hilda on Thursday
= 22 - 1 p
= 22 - 2
= $20
2 u = 20
1 u = 20 ÷ 2 = 10
Amount that Marion had at first
= 3 u
= 3 x 10
= $30
Total amount that Marion and Hilda had
= 22 + 6
= $28
Amount that Hilda had at first
= 28 - 30
= $-2
Amount that Marion had more than Hilda
= 30 - -2
= $32
Answer(s): $32
