Mrs Lim gave Dana and Kimberly some money each on Monday. On Tuesday, Dana gave
13 of the amount she had to Kimberly. On Wednesday, Kimberly gave
15 of the amount she had to Dana. In the end, Dana had $20 and Kimberly had $8. How much did Kimberly had more than Dana at first?
|
Dana |
Kimberly |
Total |
Before 1 |
3 u |
? |
$28 |
Change 1 |
- 1 u |
+ 1 u |
|
After 1 |
2 u |
5 p |
$28 |
Before 2 |
$20 - 1 p |
5 p |
$28 |
Change 2 |
+ 1 p |
- 1 p |
|
After 2 |
$20 |
4 p ($8) |
$28 |
Amount that Kimberly had in the end = 4 p
4 p = 8
1 p = 8 ÷ 4 = 2
Working backwards.
Amount that Dana had after giving to Kimberly on Tuesday
= 20 - 1 p
= 20 - 2
= $18
2 u = 18
1 u = 18 ÷ 2 = 9
Amount that Dana had at first
= 3 u
= 3 x 9
= $27
Total amount that Dana and Kimberly had
= 20 + 8
= $28
Amount that Kimberly had at first
= 28 - 27
= $1
Amount that Dana had more than Kimberly
= 27 - 1
= $26
Answer(s): $26