Mrs Choy gave Kathy and Min some money each on Wednesday. On Thursday, Kathy gave
15 of the amount she had to Min. On Friday, Min gave
14 of the amount she had to Kathy. In the end, Kathy had $47 and Min had $21. How much did Min had more than Kathy at first?
| |
Kathy |
Min |
Total |
| Before 1 |
5 u |
? |
$68 |
| Change 1 |
- 1 u |
+ 1 u |
|
| After 1 |
4 u |
4 p |
$68 |
| Before 2 |
$47 - 1 p |
4 p |
$68 |
| Change 2 |
+ 1 p |
- 1 p |
|
After 2 |
$47 |
3 p
($21) |
$68 |
Amount that Min had in the end = 3 p
3 p = 21
1 p = 21 ÷ 3 = 7
Working backwards.
Amount that Kathy had after giving to Min on Thursday
= 47 - 1 p
= 47 - 7
= $40
4 u = 40
1 u = 40 ÷ 4 = 10
Amount that Kathy had at first
= 5 u
= 5 x 10
= $50
Total amount that Kathy and Min had
= 47 + 21
= $68
Amount that Min had at first
= 68 - 50
= $18
Amount that Kathy had more than Min
= 50 - 18
= $32
Answer(s): $32
