Mrs Yee gave Yen and Yoko some money each on Thursday. On Friday, Yen gave
15 of the amount she had to Yoko. On Saturday, Yoko gave
16 of the amount she had to Yen. In the end, Yen had $18 and Yoko had $10. How much did Yoko had more than Yen at first?
| |
Yen |
Yoko |
Total |
| Before 1 |
5 u |
? |
$28 |
| Change 1 |
- 1 u |
+ 1 u |
|
| After 1 |
4 u |
6 p |
$28 |
| Before 2 |
$18 - 1 p |
6 p |
$28 |
| Change 2 |
+ 1 p |
- 1 p |
|
After 2 |
$18 |
5 p
($10) |
$28 |
Amount that Yoko had in the end = 5 p
5 p = 10
1 p = 10 ÷ 5 = 2
Working backwards.
Amount that Yen had after giving to Yoko on Friday
= 18 - 1 p
= 18 - 2
= $16
4 u = 16
1 u = 16 ÷ 4 = 4
Amount that Yen had at first
= 5 u
= 5 x 4
= $20
Total amount that Yen and Yoko had
= 18 + 10
= $28
Amount that Yoko had at first
= 28 - 20
= $8
Amount that Yen had more than Yoko
= 20 - 8
= $12
Answer(s): $12
