Mrs Yeo gave Risa and Gillian some money each on Thursday. On Friday, Risa gave
13 of the amount she had to Gillian. On Saturday, Gillian gave
14 of the amount she had to Risa. In the end, Risa had $23 and Gillian had $9. How much did Gillian had more than Risa at first?
| |
Risa |
Gillian |
Total |
| Before 1 |
3 u |
? |
$32 |
| Change 1 |
- 1 u |
+ 1 u |
|
| After 1 |
2 u |
4 p |
$32 |
| Before 2 |
$23 - 1 p |
4 p |
$32 |
| Change 2 |
+ 1 p |
- 1 p |
|
After 2 |
$23 |
3 p
($9) |
$32 |
Amount that Gillian had in the end = 3 p
3 p = 9
1 p = 9 ÷ 3 = 3
Working backwards.
Amount that Risa had after giving to Gillian on Friday
= 23 - 1 p
= 23 - 3
= $20
2 u = 20
1 u = 20 ÷ 2 = 10
Amount that Risa had at first
= 3 u
= 3 x 10
= $30
Total amount that Risa and Gillian had
= 23 + 9
= $32
Amount that Gillian had at first
= 32 - 30
= $2
Amount that Risa had more than Gillian
= 30 - 2
= $28
Answer(s): $28
