Mrs Leng gave Jade and Dana some money each on Thursday. On Friday, Jade gave
16 of the amount she had to Dana. On Saturday, Dana gave
13 of the amount she had to Jade. In the end, Jade had $43 and Dana had $6. How much did Dana had more than Jade at first?
| |
Jade |
Dana |
Total |
| Before 1 |
6 u |
? |
$49 |
| Change 1 |
- 1 u |
+ 1 u |
|
| After 1 |
5 u |
3 p |
$49 |
| Before 2 |
$43 - 1 p |
3 p |
$49 |
| Change 2 |
+ 1 p |
- 1 p |
|
After 2 |
$43 |
2 p
($6) |
$49 |
Amount that Dana had in the end = 2 p
2 p = 6
1 p = 6 ÷ 2 = 3
Working backwards.
Amount that Jade had after giving to Dana on Friday
= 43 - 1 p
= 43 - 3
= $40
5 u = 40
1 u = 40 ÷ 5 = 8
Amount that Jade had at first
= 6 u
= 6 x 8
= $48
Total amount that Jade and Dana had
= 43 + 6
= $49
Amount that Dana had at first
= 49 - 48
= $1
Amount that Jade had more than Dana
= 48 - 1
= $47
Answer(s): $47
