Mrs Yeo gave Shiyun and Usha some money each on Thursday. On Friday, Shiyun gave
16 of the amount she had to Usha. On Saturday, Usha gave
15 of the amount she had to Shiyun. In the end, Shiyun had $44 and Usha had $16. How much did Usha had more than Shiyun at first?
| |
Shiyun |
Usha |
Total |
| Before 1 |
6 u |
? |
$60 |
| Change 1 |
- 1 u |
+ 1 u |
|
| After 1 |
5 u |
5 p |
$60 |
| Before 2 |
$44 - 1 p |
5 p |
$60 |
| Change 2 |
+ 1 p |
- 1 p |
|
After 2 |
$44 |
4 p
($16) |
$60 |
Amount that Usha had in the end = 4 p
4 p = 16
1 p = 16 ÷ 4 = 4
Working backwards.
Amount that Shiyun had after giving to Usha on Friday
= 44 - 1 p
= 44 - 4
= $40
5 u = 40
1 u = 40 ÷ 5 = 8
Amount that Shiyun had at first
= 6 u
= 6 x 8
= $48
Total amount that Shiyun and Usha had
= 44 + 16
= $60
Amount that Usha had at first
= 60 - 48
= $12
Amount that Shiyun had more than Usha
= 48 - 12
= $36
Answer(s): $36
