Mrs Quek gave Xylia and Betty some money each on Tuesday. On Wednesday, Xylia gave
15 of the amount she had to Betty. On Thursday, Betty gave
13 of the amount she had to Xylia. In the end, Xylia had $32 and Betty had $8. How much did Betty had more than Xylia at first?
| |
Xylia |
Betty |
Total |
| Before 1 |
5 u |
? |
$40 |
| Change 1 |
- 1 u |
+ 1 u |
|
| After 1 |
4 u |
3 p |
$40 |
| Before 2 |
$32 - 1 p |
3 p |
$40 |
| Change 2 |
+ 1 p |
- 1 p |
|
After 2 |
$32 |
2 p
($8) |
$40 |
Amount that Betty had in the end = 2 p
2 p = 8
1 p = 8 ÷ 2 = 4
Working backwards.
Amount that Xylia had after giving to Betty on Wednesday
= 32 - 1 p
= 32 - 4
= $28
4 u = 28
1 u = 28 ÷ 4 = 7
Amount that Xylia had at first
= 5 u
= 5 x 7
= $35
Total amount that Xylia and Betty had
= 32 + 8
= $40
Amount that Betty had at first
= 40 - 35
= $5
Amount that Xylia had more than Betty
= 35 - 5
= $30
Answer(s): $30
