Mrs Yeo gave Natalie and Nora some money each on Tuesday. On Wednesday, Natalie gave
15 of the amount she had to Nora. On Thursday, Nora gave
16 of the amount she had to Natalie. In the end, Natalie had $49 and Nora had $25. How much did Nora had more than Natalie at first?
|
Natalie |
Nora |
Total |
Before 1 |
5 u |
? |
$74 |
Change 1 |
- 1 u |
+ 1 u |
|
After 1 |
4 u |
6 p |
$74 |
Before 2 |
$49 - 1 p |
6 p |
$74 |
Change 2 |
+ 1 p |
- 1 p |
|
After 2 |
$49 |
5 p ($25) |
$74 |
Amount that Nora had in the end = 5 p
5 p = 25
1 p = 25 ÷ 5 = 5
Working backwards.
Amount that Natalie had after giving to Nora on Wednesday
= 49 - 1 p
= 49 - 5
= $44
4 u = 44
1 u = 44 ÷ 4 = 11
Amount that Natalie had at first
= 5 u
= 5 x 11
= $55
Total amount that Natalie and Nora had
= 49 + 25
= $74
Amount that Nora had at first
= 74 - 55
= $19
Amount that Natalie had more than Nora
= 55 - 19
= $36
Answer(s): $36