Mrs Lim gave Yoko and Elyse some money each on Thursday. On Friday, Yoko gave
16 of the amount she had to Elyse. On Saturday, Elyse gave
13 of the amount she had to Yoko. In the end, Yoko had $62 and Elyse had $14. How much did Elyse had more than Yoko at first?
| |
Yoko |
Elyse |
Total |
| Before 1 |
6 u |
? |
$76 |
| Change 1 |
- 1 u |
+ 1 u |
|
| After 1 |
5 u |
3 p |
$76 |
| Before 2 |
$62 - 1 p |
3 p |
$76 |
| Change 2 |
+ 1 p |
- 1 p |
|
After 2 |
$62 |
2 p
($14) |
$76 |
Amount that Elyse had in the end = 2 p
2 p = 14
1 p = 14 ÷ 2 = 7
Working backwards.
Amount that Yoko had after giving to Elyse on Friday
= 62 - 1 p
= 62 - 7
= $55
5 u = 55
1 u = 55 ÷ 5 = 11
Amount that Yoko had at first
= 6 u
= 6 x 11
= $66
Total amount that Yoko and Elyse had
= 62 + 14
= $76
Amount that Elyse had at first
= 76 - 66
= $10
Amount that Yoko had more than Elyse
= 66 - 10
= $56
Answer(s): $56
