Mrs Quek gave Dana and Marion some money each on Monday. On Tuesday, Dana gave
16 of the amount she had to Marion. On Wednesday, Marion gave
14 of the amount she had to Dana. In the end, Dana had $45 and Marion had $30. How much did Marion had more than Dana at first?
| |
Dana |
Marion |
Total |
| Before 1 |
6 u |
? |
$75 |
| Change 1 |
- 1 u |
+ 1 u |
|
| After 1 |
5 u |
4 p |
$75 |
| Before 2 |
$45 - 1 p |
4 p |
$75 |
| Change 2 |
+ 1 p |
- 1 p |
|
After 2 |
$45 |
3 p
($30) |
$75 |
Amount that Marion had in the end = 3 p
3 p = 30
1 p = 30 ÷ 3 = 10
Working backwards.
Amount that Dana had after giving to Marion on Tuesday
= 45 - 1 p
= 45 - 10
= $35
5 u = 35
1 u = 35 ÷ 5 = 7
Amount that Dana had at first
= 6 u
= 6 x 7
= $42
Total amount that Dana and Marion had
= 45 + 30
= $75
Amount that Marion had at first
= 75 - 42
= $33
Amount that Dana had more than Marion
= 42 - 33
= $9
Answer(s): $9
