Mrs Chew gave Irene and Yoko some money each on Thursday. On Friday, Irene gave
15 of the amount she had to Yoko. On Saturday, Yoko gave
14 of the amount she had to Irene. In the end, Irene had $15 and Yoko had $9. How much did Yoko had more than Irene at first?
| |
Irene |
Yoko |
Total |
| Before 1 |
5 u |
? |
$24 |
| Change 1 |
- 1 u |
+ 1 u |
|
| After 1 |
4 u |
4 p |
$24 |
| Before 2 |
$15 - 1 p |
4 p |
$24 |
| Change 2 |
+ 1 p |
- 1 p |
|
After 2 |
$15 |
3 p
($9) |
$24 |
Amount that Yoko had in the end = 3 p
3 p = 9
1 p = 9 ÷ 3 = 3
Working backwards.
Amount that Irene had after giving to Yoko on Friday
= 15 - 1 p
= 15 - 3
= $12
4 u = 12
1 u = 12 ÷ 4 = 3
Amount that Irene had at first
= 5 u
= 5 x 3
= $15
Total amount that Irene and Yoko had
= 15 + 9
= $24
Amount that Yoko had at first
= 24 - 15
= $9
Amount that Irene had more than Yoko
= 15 - 9
= $6
Answer(s): $6
