Mrs Loo gave Min and Elyse some money each on Wednesday. On Thursday, Min gave
15 of the amount she had to Elyse. On Friday, Elyse gave
13 of the amount she had to Min. In the end, Min had $28 and Elyse had $8. How much did Elyse had more than Min at first?
| |
Min |
Elyse |
Total |
| Before 1 |
5 u |
? |
$36 |
| Change 1 |
- 1 u |
+ 1 u |
|
| After 1 |
4 u |
3 p |
$36 |
| Before 2 |
$28 - 1 p |
3 p |
$36 |
| Change 2 |
+ 1 p |
- 1 p |
|
After 2 |
$28 |
2 p
($8) |
$36 |
Amount that Elyse had in the end = 2 p
2 p = 8
1 p = 8 ÷ 2 = 4
Working backwards.
Amount that Min had after giving to Elyse on Thursday
= 28 - 1 p
= 28 - 4
= $24
4 u = 24
1 u = 24 ÷ 4 = 6
Amount that Min had at first
= 5 u
= 5 x 6
= $30
Total amount that Min and Elyse had
= 28 + 8
= $36
Amount that Elyse had at first
= 36 - 30
= $6
Amount that Min had more than Elyse
= 30 - 6
= $24
Answer(s): $24
