Victoria had a total of 409 blue and white balls. She used
45 of her blue balls and bought another 53 white balls. The number of white balls she had then become
14 the number of blue balls. How many less white balls than blue balls did she have at first?
| |
Blue balls |
White balls |
| Before |
5x4 |
|
| Change |
- 4x4 |
+ 53 |
| After |
1x4 |
|
| Comparing balls in the end |
4x1 |
1x1 |
| |
Blue balls |
White balls |
| Before |
20 u |
1 u - 53 |
| Change |
- 16 u |
+ 53 |
| After |
4 u |
1 u |
The number of blue balls in the end is repeated.
LCM of 1 and 4 is 4.
Total number of blue balls and white balls
= 20 u + 1 u - 53
= 21 u - 53
21 u - 53 = 409
21 u = 409 + 53
21 u = 462
1 u = 462 ÷ 21 = 22
Number of less white balls than blue balls at first
= 20 u - (1 u - 53)
= 19 u + 53
= 19 x 22 + 53
= 471
Answer(s): 471
