Roshel had a total of 411 brown and green balls. She used
35 of her brown balls and bought another 65 green balls. The number of green balls she had then become
13 the number of brown balls. How many less green balls than brown balls did she have at first?
| |
Brown balls |
Green balls |
| Before |
5x3 |
|
| Change |
- 3x3 |
+ 65 |
| After |
2x3 |
|
| Comparing balls in the end |
3x2 |
1x2 |
| |
Brown balls |
Green balls |
| Before |
15 u |
2 u - 65 |
| Change |
- 9 u |
+ 65 |
| After |
6 u |
2 u |
The number of brown balls in the end is repeated.
LCM of 2 and 3 is 6.
Total number of brown balls and green balls
= 15 u + 2 u - 65
= 17 u - 65
17 u - 65 = 411
17 u = 411 + 65
17 u = 476
1 u = 476 ÷ 17 = 28
Number of less green balls than brown balls at first
= 15 u - (2 u - 65)
= 13 u + 65
= 13 x 28 + 65
= 429
Answer(s): 429
