Gillian had a total of 442 purple and blue balls. She used
35 of her purple balls and bought another 44 blue balls. The number of blue balls she had then become
15 the number of purple balls. How many less blue balls than purple balls did she have at first?
|
Purple balls |
Blue balls |
Before |
5x5 |
|
Change |
- 3x5 |
+ 44 |
After |
2x5 |
|
Comparing balls in the end |
5x2 |
1x2 |
|
Purple balls |
Blue balls |
Before |
25 u |
2 u - 44 |
Change |
- 15 u |
+ 44 |
After |
10 u |
2 u |
The number of purple balls in the end is repeated.
LCM of 2 and 5 is 10.
Total number of purple balls and blue balls
= 25 u + 2 u - 44
= 27 u - 44
27 u - 44 = 442
27 u = 442 + 44
27 u = 486
1 u = 486 ÷ 27 = 18
Number of less blue balls than purple balls at first
= 25 u - (2 u - 44)
= 23 u + 44
= 23 x 18 + 44
= 458
Answer(s): 458