Tina had a total of 331 pink and silver balls. She used
45 of her pink balls and bought another 53 silver balls. The number of silver balls she had then become
13 the number of pink balls. How many less silver balls than pink balls did she have at first?
| |
Pink balls |
Silver balls |
| Before |
5x3 |
|
| Change |
- 4x3 |
+ 53 |
| After |
1x3 |
|
| Comparing balls in the end |
3x1 |
1x1 |
| |
Pink balls |
Silver balls |
| Before |
15 u |
1 u - 53 |
| Change |
- 12 u |
+ 53 |
| After |
3 u |
1 u |
The number of pink balls in the end is repeated.
LCM of 1 and 3 is 3.
Total number of pink balls and silver balls
= 15 u + 1 u - 53
= 16 u - 53
16 u - 53 = 331
16 u = 331 + 53
16 u = 384
1 u = 384 ÷ 16 = 24
Number of less silver balls than pink balls at first
= 15 u - (1 u - 53)
= 14 u + 53
= 14 x 24 + 53
= 389
Answer(s): 389
