Victoria had a total of 216 yellow and blue beads. She used
45 of her yellow beads and bought another 36 blue beads. The number of blue beads she had then become
14 the number of yellow beads. How many less blue beads than yellow beads did she have at first?
| |
Yellow beads |
Blue beads |
| Before |
5x4 |
|
| Change |
- 4x4 |
+ 36 |
| After |
1x4 |
|
| Comparing beads in the end |
4x1 |
1x1 |
| |
Yellow beads |
Blue beads |
| Before |
20 u |
1 u - 36 |
| Change |
- 16 u |
+ 36 |
| After |
4 u |
1 u |
The number of yellow beads in the end is repeated.
LCM of 1 and 4 is 4.
Total number of yellow beads and blue beads
= 20 u + 1 u - 36
= 21 u - 36
21 u - 36 = 216
21 u = 216 + 36
21 u = 252
1 u = 252 ÷ 21 = 12
Number of less blue beads than yellow beads at first
= 20 u - (1 u - 36)
= 19 u + 36
= 19 x 12 + 36
= 264
Answer(s): 264
