Victoria had a total of 410 pink and white balls. She used
45 of her pink balls and bought another 52 white balls. The number of white balls she had then become
14 the number of pink balls. How many less white balls than pink balls did she have at first?
| |
Pink balls |
White balls |
| Before |
5x4 |
|
| Change |
- 4x4 |
+ 52 |
| After |
1x4 |
|
| Comparing balls in the end |
4x1 |
1x1 |
| |
Pink balls |
White balls |
| Before |
20 u |
1 u - 52 |
| Change |
- 16 u |
+ 52 |
| After |
4 u |
1 u |
The number of pink balls in the end is repeated.
LCM of 1 and 4 is 4.
Total number of pink balls and white balls
= 20 u + 1 u - 52
= 21 u - 52
21 u - 52 = 410
21 u = 410 + 52
21 u = 462
1 u = 462 ÷ 21 = 22
Number of less white balls than pink balls at first
= 20 u - (1 u - 52)
= 19 u + 52
= 19 x 22 + 52
= 470
Answer(s): 470
