Yoko had a total of 274 blue and silver beads. She used
47 of her blue beads and bought another 67 silver beads. The number of silver beads she had then become
14 the number of blue beads. How many less silver beads than blue beads did she have at first?
| |
Blue beads |
Silver beads |
| Before |
7x4 |
|
| Change |
- 4x4 |
+ 67 |
| After |
3x4 |
|
| Comparing beads in the end |
4x3 |
1x3 |
| |
Blue beads |
Silver beads |
| Before |
28 u |
3 u - 67 |
| Change |
- 16 u |
+ 67 |
| After |
12 u |
3 u |
The number of blue beads in the end is repeated.
LCM of 3 and 4 is 12.
Total number of blue beads and silver beads
= 28 u + 3 u - 67
= 31 u - 67
31 u - 67 = 274
31 u = 274 + 67
31 u = 341
1 u = 341 ÷ 31 = 11
Number of less silver beads than blue beads at first
= 28 u - (3 u - 67)
= 25 u + 67
= 25 x 11 + 67
= 342
Answer(s): 342
