Xylia had a total of 232 silver and yellow balls. She used
37 of her silver balls and bought another 41 yellow balls. The number of yellow balls she had then become
15 the number of silver balls. How many less yellow balls than silver balls did she have at first?
| |
Silver balls |
Yellow balls |
| Before |
7x5 |
|
| Change |
- 3x5 |
+ 41 |
| After |
4x5 |
|
| Comparing balls in the end |
5x4 |
1x4 |
| |
Silver balls |
Yellow balls |
| Before |
35 u |
4 u - 41 |
| Change |
- 15 u |
+ 41 |
| After |
20 u |
4 u |
The number of silver balls in the end is repeated.
LCM of 4 and 5 is 20.
Total number of silver balls and yellow balls
= 35 u + 4 u - 41
= 39 u - 41
39 u - 41 = 232
39 u = 232 + 41
39 u = 273
1 u = 273 ÷ 39 = 7
Number of less yellow balls than silver balls at first
= 35 u - (4 u - 41)
= 31 u + 41
= 31 x 7 + 41
= 258
Answer(s): 258
