Mary had a total of 241 green and blue balls. She used
47 of her green balls and bought another 38 blue balls. The number of blue balls she had then become
14 the number of green balls. How many less blue balls than green balls did she have at first?
|
Green balls |
Blue balls |
Before |
7x4 |
|
Change |
- 4x4 |
+ 38 |
After |
3x4 |
|
Comparing balls in the end |
4x3 |
1x3 |
|
Green balls |
Blue balls |
Before |
28 u |
3 u - 38 |
Change |
- 16 u |
+ 38 |
After |
12 u |
3 u |
The number of green balls in the end is repeated.
LCM of 3 and 4 is 12.
Total number of green balls and blue balls
= 28 u + 3 u - 38
= 31 u - 38
31 u - 38 = 241
31 u = 241 + 38
31 u = 279
1 u = 279 ÷ 31 = 9
Number of less blue balls than green balls at first
= 28 u - (3 u - 38)
= 25 u + 38
= 25 x 9 + 38
= 263
Answer(s): 263