Nicole had a total of 446 red and yellow balls. She used
35 of her red balls and bought another 67 yellow balls. The number of yellow balls she had then become
15 the number of red balls. How many less yellow balls than red balls did she have at first?
|
Red balls |
Yellow balls |
Before |
5x5 |
|
Change |
- 3x5 |
+ 67 |
After |
2x5 |
|
Comparing balls in the end |
5x2 |
1x2 |
|
Red balls |
Yellow balls |
Before |
25 u |
2 u - 67 |
Change |
- 15 u |
+ 67 |
After |
10 u |
2 u |
The number of red balls in the end is repeated.
LCM of 2 and 5 is 10.
Total number of red balls and yellow balls
= 25 u + 2 u - 67
= 27 u - 67
27 u - 67 = 446
27 u = 446 + 67
27 u = 513
1 u = 513 ÷ 27 = 19
Number of less yellow balls than red balls at first
= 25 u - (2 u - 67)
= 23 u + 67
= 23 x 19 + 67
= 504
Answer(s): 504