Shannon had a total of 237 blue and gold balls. She used
45 of her blue balls and bought another 36 gold balls. The number of gold balls she had then become
14 the number of blue balls. How many less gold balls than blue balls did she have at first?
|
Blue balls |
Gold balls |
Before |
5x4 |
|
Change |
- 4x4 |
+ 36 |
After |
1x4 |
|
Comparing balls in the end |
4x1 |
1x1 |
|
Blue balls |
Gold balls |
Before |
20 u |
1 u - 36 |
Change |
- 16 u |
+ 36 |
After |
4 u |
1 u |
The number of blue balls in the end is repeated.
LCM of 1 and 4 is 4.
Total number of blue balls and gold balls
= 20 u + 1 u - 36
= 21 u - 36
21 u - 36 = 237
21 u = 237 + 36
21 u = 273
1 u = 273 ÷ 21 = 13
Number of less gold balls than blue balls at first
= 20 u - (1 u - 36)
= 19 u + 36
= 19 x 13 + 36
= 283
Answer(s): 283