Gem had a total of 114 pieces of $5 and $20 notes at first. She spent
58 of the number of $5 notes and received another 7 pieces of $20 notes from her mother. After that, the number of $20 notes she had was
12 of the remaining notes. How much money did Gem have at first?
|
$5 |
$20 |
Total |
Before |
8 u |
3 u - 7 |
114 |
Change |
- 5 u |
+ 7 |
|
After |
3 u |
|
|
Comparing $5-notes and $20-notes |
1x3 = 3 u |
1x3 = 3 u |
|
The number of $5-notes and $20-notes in the end is the same.
The number of $5-notes in the end is repeated. Make the number of $5-notes in the end the same. LCM of 1 and 3 is 3.
Number of notes at first
= 8 u + 3 u - 7
= 11 u - 7
11 u - 7 = 114
11 u = 114 + 7
11 u = 121
1 u = 121 ÷ 11 = 11
Number of $5-notes at first
= 8 u
= 8 x 11
= 88
Total value of $5-notes at first
= 88 x 5
= $440
Number of $20-notes at first
= 3 u - 7
= 3 x 11 - 7
= 33 - 7
= 26
Total value of $20-notes at first
= 26 x 20
= $520
Amount that Gem had at first
= 440 + 520
= $960
Answer(s): $960