Jean had a total of 27 pieces of $50 and $2 notes at first. She spent ³₅ of the number of $50 notes and received another 8 pieces of $2 notes from her mother. After that, the number of $2 notes she had was ¹₂ of the remaining notes. How much money did Jean have at first?

	$50	$2	Total
Before	5 u	2 u - 8	27
Change	- 3 u	+ 8
After	2 u
Comparing $50-notes and $2-notes	1x2 = 2 u	1x2 = 2 u

The number of $50-notes and $2-notes in the end is the same.

The number of $50-notes in the end is repeated.  Make the number of $50-notes in the end the same. LCM of 1 and 2 is 2.

Number of notes at first
= 5 u + 2 u - 8
= 7 u - 8

7 u - 8 = 27
7 u = 27 + 8
7 u = 35

1 u = 35 ÷  7 = 5

Number of $50-notes at first
= 5 u
= 5 x 5
= 25

Total value of $50-notes at first
= 25 x 50
= $1250

Number of $2-notes at first
= 2 u - 8
= 2 x 5 - 8
= 10 - 8
= 2

Total value of $2-notes at first
= 2 x 2
= $4

Amount that Jean had at first
= 1250 + 4 
= $1254

Answer(s): $1254