Julie had a total of 72 pieces of $10 and $20 notes at first. She spent
35 of the number of $10 notes and received another 12 pieces of $20 notes from her mother. After that, the number of $20 notes she had was
12 of the remaining notes. How much money did Julie have at first?
|
$10 |
$20 |
Total |
Before |
5 u |
2 u - 12 |
72 |
Change |
- 3 u |
+ 12 |
|
After |
2 u |
|
|
Comparing $10-notes and $20-notes |
1x2 = 2 u |
1x2 = 2 u |
|
The number of $10-notes and $20-notes in the end is the same.
The number of $10-notes in the end is repeated. Make the number of $10-notes in the end the same. LCM of 1 and 2 is 2.
Number of notes at first
= 5 u + 2 u - 12
= 7 u - 12
7 u - 12 = 72
7 u = 72 + 12
7 u = 84
1 u = 84 ÷ 7 = 12
Number of $10-notes at first
= 5 u
= 5 x 12
= 60
Total value of $10-notes at first
= 60 x 10
= $600
Number of $20-notes at first
= 2 u - 12
= 2 x 12 - 12
= 24 - 12
= 12
Total value of $20-notes at first
= 12 x 20
= $240
Amount that Julie had at first
= 600 + 240
= $840
Answer(s): $840