Sabrina had a total of 83 pieces of $50 and $10 notes at first. She spent
47 of the number of $50 notes and received another 7 pieces of $10 notes from her mother. After that, the number of $10 notes she had was
12 of the remaining notes. How much money did Sabrina have at first?
|
$50 |
$10 |
Total |
Before |
7 u |
3 u - 7 |
83 |
Change |
- 4 u |
+ 7 |
|
After |
3 u |
|
|
Comparing $50-notes and $10-notes |
1x3 = 3 u |
1x3 = 3 u |
|
The number of $50-notes and $10-notes in the end is the same.
The number of $50-notes in the end is repeated. Make the number of $50-notes in the end the same. LCM of 1 and 3 is 3.
Number of notes at first
= 7 u + 3 u - 7
= 10 u - 7
10 u - 7 = 83
10 u = 83 + 7
10 u = 90
1 u = 90 ÷ 10 = 9
Number of $50-notes at first
= 7 u
= 7 x 9
= 63
Total value of $50-notes at first
= 63 x 50
= $3150
Number of $10-notes at first
= 3 u - 7
= 3 x 9 - 7
= 27 - 7
= 20
Total value of $10-notes at first
= 20 x 10
= $200
Amount that Sabrina had at first
= 3150 + 200
= $3350
Answer(s): $3350