Zoe had a total of 89 pieces of $10 and $2 notes at first. She spent
27 of the number of $10 notes and received another 7 pieces of $2 notes from her mother. After that, the number of $2 notes she had was
12 of the remaining notes. How much money did Zoe have at first?
|
$10 |
$2 |
Total |
Before |
7 u |
5 u - 7 |
89 |
Change |
- 2 u |
+ 7 |
|
After |
5 u |
|
|
Comparing $10-notes and $2-notes |
1x5 = 5 u |
1x5 = 5 u |
|
The number of $10-notes and $2-notes in the end is the same.
The number of $10-notes in the end is repeated. Make the number of $10-notes in the end the same. LCM of 1 and 5 is 5.
Number of notes at first
= 7 u + 5 u - 7
= 12 u - 7
12 u - 7 = 89
12 u = 89 + 7
12 u = 96
1 u = 96 ÷ 12 = 8
Number of $10-notes at first
= 7 u
= 7 x 8
= 56
Total value of $10-notes at first
= 56 x 10
= $560
Number of $2-notes at first
= 5 u - 7
= 5 x 8 - 7
= 40 - 7
= 33
Total value of $2-notes at first
= 33 x 2
= $66
Amount that Zoe had at first
= 560 + 66
= $626
Answer(s): $626