Nicole had a total of 8 pieces of $50 and $5 notes at first. She spent ³₅ of the number of $50 notes and received another 6 pieces of $5 notes from her mother. After that, the number of $5 notes she had was ¹₂ of the remaining notes. How much money did Nicole have at first?

	$50	$5	Total
Before	5 u	2 u - 6	8
Change	- 3 u	+ 6
After	2 u
Comparing $50-notes and $5-notes	1x2 = 2 u	1x2 = 2 u

The number of $50-notes and $5-notes in the end is the same.

The number of $50-notes in the end is repeated.  Make the number of $50-notes in the end the same. LCM of 1 and 2 is 2.

Number of notes at first
= 5 u + 2 u - 6
= 7 u - 6

7 u - 6 = 8
7 u = 8 + 6
7 u = 14

1 u = 14 ÷  7 = 2

Number of $50-notes at first
= 5 u
= 5 x 2
= 10

Total value of $50-notes at first
= 10 x 50
= $500

Number of $5-notes at first
= 2 u - 6
= 2 x 2 - 6
= 4 - 6
= -2

Total value of $5-notes at first
= -2 x 5
= $-10

Amount that Nicole had at first
= 500 + -10 
= $490

Answer(s): $490