Linda had a total of 49 pieces of $5 and $100 notes at first. She spent
57 of the number of $5 notes and received another 5 pieces of $100 notes from her mother. After that, the number of $100 notes she had was
12 of the remaining notes. How much money did Linda have at first?
|
$5 |
$100 |
Total |
Before |
7 u |
2 u - 5 |
49 |
Change |
- 5 u |
+ 5 |
|
After |
2 u |
|
|
Comparing $5-notes and $100-notes |
1x2 = 2 u |
1x2 = 2 u |
|
The number of $5-notes and $100-notes in the end is the same.
The number of $5-notes in the end is repeated. Make the number of $5-notes in the end the same. LCM of 1 and 2 is 2.
Number of notes at first
= 7 u + 2 u - 5
= 9 u - 5
9 u - 5 = 49
9 u = 49 + 5
9 u = 54
1 u = 54 ÷ 9 = 6
Number of $5-notes at first
= 7 u
= 7 x 6
= 42
Total value of $5-notes at first
= 42 x 5
= $210
Number of $100-notes at first
= 2 u - 5
= 2 x 6 - 5
= 12 - 5
= 7
Total value of $100-notes at first
= 7 x 100
= $700
Amount that Linda had at first
= 210 + 700
= $910
Answer(s): $910