Min had a total of 42 pieces of $5 and $20 notes at first. She spent
38 of the number of $5 notes and received another 10 pieces of $20 notes from her mother. After that, the number of $20 notes she had was
12 of the remaining notes. How much money did Min have at first?
|
$5 |
$20 |
Total |
Before |
8 u |
5 u - 10 |
42 |
Change |
- 3 u |
+ 10 |
|
After |
5 u |
|
|
Comparing $5-notes and $20-notes |
1x5 = 5 u |
1x5 = 5 u |
|
The number of $5-notes and $20-notes in the end is the same.
The number of $5-notes in the end is repeated. Make the number of $5-notes in the end the same. LCM of 1 and 5 is 5.
Number of notes at first
= 8 u + 5 u - 10
= 13 u - 10
13 u - 10 = 42
13 u = 42 + 10
13 u = 52
1 u = 52 ÷ 13 = 4
Number of $5-notes at first
= 8 u
= 8 x 4
= 32
Total value of $5-notes at first
= 32 x 5
= $160
Number of $20-notes at first
= 5 u - 10
= 5 x 4 - 10
= 20 - 10
= 10
Total value of $20-notes at first
= 10 x 20
= $200
Amount that Min had at first
= 160 + 200
= $360
Answer(s): $360