Xavier had some pastries.
35 of them were croissants. The rest were cookies. He sold
56 of the croissants and 14 cookies. In the end, he had 11 pastries left. How many pastries did he sell?
| |
Croissants |
Cookies |
Comparing pastries
at first |
3x2 =
6 u |
2x2 =
4 u |
Before
|
6x1 =
6 u |
4 u |
Change
|
- 5x1 =
- 5 u |
- 14 |
After
|
1x1 =
1 u |
4 u - 14 |
The number of croissants at first is repeated. Make the number of croissants at first the same. LCM of 3 and 6 is 6.
Total number of pastries left
= 1 u + 4 u - 14
= 5 u - 14
5 u - 14 = 11
5 u = 11 + 14
5 u = 25
1 u = 25 ÷ 5 = 5
Number of pastries that Xavier sold
= 5 u + 14
= 5 x 5 + 14
= 25 + 14
= 39
Answer(s): 39
