Ahmad had some pastries.
35 of them were biscuits. The rest were croissants. He sold
56 of the biscuits and 5 croissants. In the end, he had 35 pastries left. How many pastries did he sell?
| |
Biscuits |
Croissants |
Comparing pastries
at first |
3x2 =
6 u |
2x2 =
4 u |
Before
|
6x1 =
6 u |
4 u |
Change
|
- 5x1 =
- 5 u |
- 5 |
After
|
1x1 =
1 u |
4 u - 5 |
The number of biscuits at first is repeated. Make the number of biscuits at first the same. LCM of 3 and 6 is 6.
Total number of pastries left
= 1 u + 4 u - 5
= 5 u - 5
5 u - 5 = 35
5 u = 35 + 5
5 u = 40
1 u = 40 ÷ 5 = 8
Number of pastries that Ahmad sold
= 5 u + 5
= 5 x 8 + 5
= 40 + 5
= 45
Answer(s): 45
