Perry had some pastries.
38 of them were cookies. The rest were croissants. He sold
56 of the cookies and 5 croissants. In the end, he had 28 pastries left. How many more cookies than croissants did he sell?
| |
Cookies |
Croissants |
Comparing pastries
at first |
3x2 =
6 u |
5x2 =
10 u |
Before
|
6x1 =
6 u |
10 u |
Change
|
- 5x1 =
- 5 u |
- 5 |
After
|
1x1 =
1 u |
10 u - 5 |
The number of cookies at first is repeated. Make the number of cookies at first the same. LCM of 3 and 6 is 6.
Total number of pastries left
= 1 u + 10 u - 5
= 11 u - 5
11 u - 5 = 28
11 u = 28 + 5
11 u = 33
1 u = 33 ÷ 11 = 3
Number of more cookies than croissants that Perry sold
= 5 u - 5
= 5 x 3 - 5
= 15 - 5
= 10
Answer(s): 10
