Archie had some pastries.
38 of them were shortbreads. The rest were croissants. He sold
34 of the shortbreads and 15 croissants. In the end, he had 146 pastries left. How many more shortbreads than croissants did he sell?
| |
Shortbreads |
Croissants |
Comparing pastries
at first |
3x4 =
12 u |
5x4 =
20 u |
Before
|
4x3 =
12 u |
20 u |
Change
|
- 3x3 =
- 9 u |
- 15 |
After
|
1x3 =
3 u |
20 u - 15 |
The number of shortbreads at first is repeated. Make the number of shortbreads at first the same. LCM of 3 and 4 is 12.
Total number of pastries left
= 3 u + 20 u - 15
= 23 u - 15
23 u - 15 = 146
23 u = 146 + 15
23 u = 161
1 u = 161 ÷ 23 = 7
Number of more shortbreads than croissants that Archie sold
= 9 u - 15
= 9 x 7 - 15
= 63 - 15
= 48
Answer(s): 48
