Bobby had some pastries.
37 of them were croissants. The rest were wafers. He sold
34 of the croissants and 14 wafers. In the end, he had 138 pastries left. How many more croissants than wafers did he sell?
|
Croissants |
Wafers |
Comparing pastries at first |
3x4 = 12 u |
4x4 = 16 u |
Before
|
4x3 = 12 u |
16 u |
Change
|
- 3x3 = - 9 u |
- 14 |
After
|
1x3 = 3 u |
16 u - 14 |
The number of croissants at first is repeated. Make the number of croissants at first the same. LCM of 3 and 4 is 12.
Total number of pastries left
= 3 u + 16 u - 14
= 19 u - 14
19 u - 14 = 138
19 u = 138 + 14
19 u = 152
1 u = 152 ÷ 19 = 8
Number of more croissants than wafers that Bobby sold
= 9 u - 14
= 9 x 8 - 14
= 72 - 14
= 58
Answer(s): 58