Peter had some pastries.
58 of them were muffins. The rest were shortbreads. He sold
34 of the muffins and 3 shortbreads. In the end, he had 48 pastries left. How many more muffins than shortbreads did he sell?
| |
Muffins |
Shortbreads |
Comparing pastries
at first |
5x4 =
20 u |
3x4 =
12 u |
Before
|
4x5 =
20 u |
12 u |
Change
|
- 3x5 =
- 15 u |
- 3 |
After
|
1x5 =
5 u |
12 u - 3 |
The number of muffins at first is repeated. Make the number of muffins at first the same. LCM of 5 and 4 is 20.
Total number of pastries left
= 5 u + 12 u - 3
= 17 u - 3
17 u - 3 = 48
17 u = 48 + 3
17 u = 51
1 u = 51 ÷ 17 = 3
Number of more muffins than shortbreads that Peter sold
= 15 u - 3
= 15 x 3 - 3
= 45 - 3
= 42
Answer(s): 42
